Nuclear Magnetic Resonance NMR spectroscopy is a powerful analytical technique used to determine the structure of organic compounds by analyzing the environment of hydrogen atoms protons within the molecule. In the case of ethanol and propanol, the structural difference can be determined by comparing their proton NMR spectra.Ethanol C2H5OH has the following structure:CH3-CH2-OHPropanol can exist in two isomeric forms: 1-propanol and 2-propanol.1-propanol C3H7OH has the following structure:CH3-CH2-CH2-OH2-propanol C3H7OH has the following structure:CH3-CHOH-CH3In the proton NMR spectra of these compounds, the hydrogen atoms in different chemical environments will give rise to distinct peaks signals with different chemical shifts measured in ppm .Ethanol:1. The CH3 group 3 protons will give a peak around 1.0-1.5 ppm methyl group .2. The CH2 group 2 protons will give a peak around 3.5-4.0 ppm methylene group adjacent to the OH group .3. The OH group 1 proton will give a broad peak around 2.5-5.0 ppm hydroxyl group .1-Propanol:1. The terminal CH3 group 3 protons will give a peak around 0.8-1.2 ppm methyl group .2. The middle CH2 group 2 protons will give a peak around 1.5-2.5 ppm methylene group adjacent to the terminal CH2 group .3. The CH2 group adjacent to the OH group 2 protons will give a peak around 3.5-4.0 ppm.4. The OH group 1 proton will give a broad peak around 2.5-5.0 ppm hydroxyl group .2-Propanol:1. The two equivalent CH3 groups 6 protons in total will give a peak around 1.0-1.5 ppm methyl groups .2. The CH group 1 proton will give a peak around 3.5-4.5 ppm methine group adjacent to the OH group .3. The OH group 1 proton will give a broad peak around 2.5-5.0 ppm hydroxyl group .By comparing the proton NMR spectra of ethanol, 1-propanol, and 2-propanol, the structural differences can be identified based on the number of peaks, their chemical shifts, and the integration proportional to the number of protons of each peak.