Iron III sulfate hexahydrate has the chemical formula Fe2 SO4 36H2O. To calculate its molar mass, we need to add the molar masses of all the atoms in the compound.Fe Iron = 55.845 g/molS Sulfur = 32.07 g/molO Oxygen = 16.00 g/molH Hydrogen = 1.008 g/molThe compound has:- 2 Iron atoms- 3 Sulfate SO4 groups, which have 1 Sulfur and 4 Oxygen atoms each- 6 Water H2O molecules, which have 2 Hydrogen and 1 Oxygen atom eachMolar mass of Fe2 SO4 36H2O = 2 55.845 + 3 1 32.07 + 4 16.00 + 6 2 1.008 + 1 16.00 = 2 55.845 + 3 32.07 + 64.00 + 6 2.016 + 16.00 = 111.69 + 3 96.07 + 6 18.016 = 111.69 + 288.21 + 108.096= 507.996 g/molSo, the molar mass of iron III sulfate hexahydrate is approximately 508 g/mol.