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What are the hybrid orbitals present in the molecule of formaldehyde (CH2O)?

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In the molecule of formaldehyde  CH2O , the central atom is carbon. The carbon atom forms two sigma bonds with two hydrogen atoms and one sigma bond with one oxygen atom. Additionally, there is a pi bond between the carbon and oxygen atoms. To determine the hybridization of the carbon atom, we can use the formula: Hybridization = 1/2 [number of valence electrons + number of monovalent atoms - charge]For carbon in formaldehyde, the formula would be:Hybridization = 1/2 [4 + 3 - 0] = 1/2 [7] = 3.5Since the hybridization value is 3.5, it indicates that the carbon atom is sp2 hybridized. Therefore, the hybrid orbitals present in the molecule of formaldehyde are sp2 orbitals for the carbon atom. The oxygen atom is also sp2 hybridized, as it forms one sigma bond with the carbon atom and has two lone pairs of electrons.
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