If the pressure is increased in the reaction N2 g + 3H2 g 2NH3 g , the equilibrium will shift towards the side with fewer moles of gas to counteract the change in pressure. In this case, there are 4 moles of gas on the reactant side 1 mole of N2 and 3 moles of H2 and 2 moles of gas on the product side 2 moles of NH3 . So, when the pressure is increased, the equilibrium will shift towards the side with fewer moles of gas, which is the product side formation of NH3 . This means that more ammonia NH3 will be produced to relieve the pressure increase.