First, we need to find the moles of sodium Na in the 5.00 grams. To do this, we will use the molar mass of sodium, which is 22.99 g/mol.moles of Na = mass of Na / molar mass of Na moles of Na = 5.00 g / 22.99 g/mol = 0.217 molesAccording to the balanced chemical equation, 2 moles of Na react with 1 mole of Cl2 to produce 2 moles of NaCl. Since we have 0.217 moles of Na, we can find the moles of NaCl produced:moles of NaCl = moles of Na = 0.217 molesNow, we can find the mass of NaCl produced by using the molar mass of NaCl, which is 58.44 g/mol 22.99 g/mol for Na + 35.45 g/mol for Cl .mass of NaCl = moles of NaCl * molar mass of NaCl mass of NaCl = 0.217 moles * 58.44 g/mol = 12.67 gTherefore, 12.67 grams of sodium chloride NaCl would be produced from the reaction of 5.00 grams of sodium Na with an excess of chlorine Cl2 gas.