Question

What is the current density in an electrochemical cell where a current of 5 amperes is passed through a copper electrode with a surface area of 0.1 square meters for 10 minutes? The half-cell reaction is: Cu2+ + 2 e- -> Cu.

Answer 1

Current density  J  is defined as the current  I  per unit area  A  of the electrode. In this case, the current  I  is 5 amperes and the surface area  A  of the copper electrode is 0.1 square meters.To calculate the current density, use the formula:J = I / AJ = 5 A / 0.1 mJ = 50 A/mSo, the current density in the electrochemical cell is 50 amperes per square meter.