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How can the concepts of chemical reactions and stoichiometry be applied to the real-world scenario of baking a cake? Specifically, how can you calculate the amount of baking soda needed to react with the amount of vinegar in a recipe to produce the optimal amount of carbon dioxide for a fluffy cake?

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To apply the concepts of chemical reactions and stoichiometry to baking a cake, we first need to understand the chemical reaction between baking soda and vinegar. Baking soda is a base  sodium bicarbonate, NaHCO3  and vinegar is an acid  acetic acid, CH3COOH . When they react, they produce carbon dioxide  CO2 , water  H2O , and sodium acetate  CH3COONa . The balanced chemical equation for this reaction is:NaHCO3 + CH3COOH  CO2 + H2O + CH3COONaNow, let's say you have a recipe that calls for a certain amount of vinegar, and you want to calculate the amount of baking soda needed to react with it completely to produce the optimal amount of CO2 for a fluffy cake.1. First, determine the amount of vinegar in the recipe  in moles . To do this, you need to know the volume of vinegar and its concentration  usually given as a percentage on the label . For example, let's say the recipe calls for 10 mL of 5% vinegar. The molar mass of acetic acid is 60.05 g/mol. 10 mL  *  1 L/1000 mL  *  5 g/100 mL  *  1 mol/60.05 g  = 0.00832 mol CH3COOH2. Use the stoichiometry of the balanced chemical equation to determine the amount of baking soda needed  in moles . Since the reaction has a 1:1 ratio between acetic acid and sodium bicarbonate, you need the same number of moles of baking soda.0.00832 mol CH3COOH *  1 mol NaHCO3/1 mol CH3COOH  = 0.00832 mol NaHCO33. Convert the amount of baking soda needed from moles to grams. The molar mass of sodium bicarbonate is 84.01 g/mol. 0.00832 mol NaHCO3  *  84.01 g/mol  = 0.699 g NaHCO3So, you would need 0.699 grams of baking soda to react completely with 10 mL of 5% vinegar in the recipe to produce the optimal amount of carbon dioxide for a fluffy cake.

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