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Given the following electrochemical reaction: Cu(s) + 2 Ag+(aq) → Cu2+(aq) + 2 Ag(s)Calculate the cell potential at standard conditions (298 K, 1 atm, 1 M concentrations).

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ago by (430 points)
To calculate the cell potential at standard conditions, we need to use the standard reduction potentials for the half-reactions involved. The half-reactions are:Cu aq  + 2e  Cu s   E = +0.34 V  reduction Ag aq  + e  Ag s   E = +0.80 V  reduction Since Cu is being oxidized, we need to reverse the first half-reaction:Cu s   Cu aq  + 2e  E = -0.34 V  oxidation Now, we can add the two half-reactions together:Cu s  + 2 Ag aq   Cu aq  + 2 Ag s To find the overall cell potential, we can add the standard potentials of the two half-reactions:E cell  = E oxidation  + E reduction E cell  = -0.34 V + 0.80 VE cell  = +0.46 VSo, the cell potential at standard conditions for this reaction is +0.46 V.

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