Question

Determine the standard enthalpy change for the reaction:   Fe2O3 (s) + 3CO (g) → 2Fe (s) + 3CO2 (g)given the following values of standard enthalpy of formation:ΔHf° [Fe2O3 (s)] = -824 kJ/mol  ΔHf° [CO2 (g)] = -393.5 kJ/mol  ΔHf° [CO (g)] = -110.5 kJ/mol  ΔHf° [Fe (s)] = 0 kJ/mol

Answer 1

To determine the standard enthalpy change for the reaction, we can use the formula:H reaction  =  Hf products  -  Hf reactants For the products:2 mol Fe  s  and 3 mol CO2  g Hf products  =  2  0 kJ/mol  +  3  -393.5 kJ/mol  = -1180.5 kJ/molFor the reactants:1 mol Fe2O3  s  and 3 mol CO  g Hf reactants  =  -824 kJ/mol  +  3  -110.5 kJ/mol  = -1155.5 kJ/molNow, we can calculate the standard enthalpy change for the reaction:H reaction  =  -1180.5 kJ/mol  -  -1155.5 kJ/mol  = -25 kJ/molThe standard enthalpy change for the reaction is -25 kJ/mol.