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Determine the oxidation state of all elements in the following compound: CoCl<sub>2</sub>•6H<sub>2</sub>O.

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In the compound CoCl<sub>2</sub>6H<sub>2</sub>O, we have three different elements: cobalt  Co , chlorine  Cl , and hydrogen  H  and oxygen  O  in the water molecules.1. Cobalt  Co : In CoCl<sub>2</sub>, the oxidation state of chlorine is -1  as a halogen, it usually has an oxidation state of -1 . Since there are two chlorine atoms, the total negative charge from chlorine is -2. To balance the charge, the oxidation state of cobalt must be +2. So, the oxidation state of Co is +2.2. Chlorine  Cl : As mentioned earlier, the oxidation state of chlorine in CoCl<sub>2</sub> is -1.3. Hydrogen  H : In the water molecules  H<sub>2</sub>O , hydrogen is bonded to oxygen. Hydrogen typically has an oxidation state of +1 when bonded to nonmetals. So, the oxidation state of H is +1.4. Oxygen  O : In the water molecules  H<sub>2</sub>O , oxygen is bonded to hydrogen. Oxygen typically has an oxidation state of -2 when bonded to nonmetals. So, the oxidation state of O is -2.In summary, the oxidation states of the elements in CoCl<sub>2</sub>6H<sub>2</sub>O are:- Cobalt  Co : +2- Chlorine  Cl : -1- Hydrogen  H : +1- Oxygen  O : -2

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