Question

Determine the equilibrium constant (Kc) for the reaction 2NO(g) + O2(g) ⇌ 2NO2(g) if the initial concentration of NO is 0.15 M, O2 is 0.10 M and NO2 is 0.30 M at equilibrium.

Answer 1

To determine the equilibrium constant  Kc  for the given reaction, we first need to write the expression for Kc. For the reaction:2NO g  + O2 g   2NO2 g The expression for Kc is:Kc = [NO2]^2 /  [NO]^2 * [O2] At equilibrium, the concentrations are given as:[NO] = 0.15 M[O2] = 0.10 M[NO2] = 0.30 MNow, we can plug these values into the Kc expression:Kc =  0.30 ^2 /   0.15 ^2 *  0.10  Kc = 0.09 /  0.0225 * 0.10 Kc = 0.09 / 0.00225Kc  40Therefore, the equilibrium constant  Kc  for the given reaction is approximately 40.