To determine the enthalpy of desorption for carbon dioxide from activated charcoal, we can use the Clausius-Clapeyron equation, which relates the vapor pressure of a substance to its temperature and enthalpy of desorption H_des :ln P2/P1 = -H_des/R * 1/T2 - 1/T1 Here, P1 and P2 are the equilibrium pressures of CO2 at temperatures T1 and T2, respectively, and R is the gas constant 8.314 J/molK .Given the equilibrium pressure of CO2 P2 at 25C 298.15 K is 0.1 atm, we need to find the reference pressure P1 at a known reference temperature T1 . Unfortunately, this information is not provided in the problem statement. To proceed, we would need either the reference pressure and temperature or the enthalpy of desorption directly. If you can provide this information, we can continue with the calculation.