Question

Determine the enthalpy change for the oxidation of 2 moles of iron (Fe) to form iron oxide (FeO) using the following data: Fe + 1/2 O2 → FeO   ΔH = -65.0 kJ/mol 4 Fe + 3 O2 → 2 Fe2O3   ΔH = -1648.6 kJ/mol

Answer 1

To determine the enthalpy change for the oxidation of 2 moles of iron  Fe  to form iron oxide  FeO , we can use the given reactions and their enthalpy changes. First, we need to manipulate the given reactions to obtain the desired reaction.Given reactions:1. Fe + 1/2 O2  FeO   H = -65.0 kJ/mol2. 4 Fe + 3 O2  2 Fe2O3   H = -1648.6 kJ/molWe need to find the enthalpy change for the following reaction:3. 2 Fe + O2  2 FeOTo obtain reaction 3, we can multiply reaction 1 by 2: 2  *  Fe + 1/2 O2  FeO  = 2 Fe + O2  2 FeONow, we can find the enthalpy change for reaction 3 by multiplying the enthalpy change of reaction 1 by 2:H3 =  2  *  -65.0 kJ/mol  = -130.0 kJ/molSo, the enthalpy change for the oxidation of 2 moles of iron  Fe  to form iron oxide  FeO  is -130.0 kJ/mol.