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Determine the activation energy for the electrochemical reaction between zinc and copper (II) sulfate solution, given that the rate constant is 2.8 x 10^-3 s^-1 at 298 K and 8.7 x 10^-3 s^-1 at 308 K.

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ago by (410 points)
To determine the activation energy  Ea  for the electrochemical reaction between zinc and copper  II  sulfate solution, we can use the Arrhenius equation:k = A * e^-Ea / RT where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant  8.314 J/molK , and T is the temperature in Kelvin.We have two sets of data: k1 = 2.8 x 10^-3 s^-1 at T1 = 298 K, and k2 = 8.7 x 10^-3 s^-1 at T2 = 308 K. We can set up two equations using the Arrhenius equation:k1 = A * e^-Ea / R * T1 k2 = A * e^-Ea / R * T2 Now, we can divide the first equation by the second equation to eliminate the pre-exponential factor  A :k1 / k2 = e^-Ea / R * T1  / e^-Ea / R * T2 Simplifying the equation:k1 / k2 = e^[ Ea / R  *  1/T2 - 1/T1 ]Now, we can plug in the given values for k1, k2, T1, and T2: 2.8 x 10^-3  /  8.7 x 10^-3  = e^[ Ea / 8.314  *  1/308 - 1/298 ]0.3218 = e^[ Ea / 8.314  *  -0.00322 ]Now, take the natural logarithm of both sides:ln 0.3218  =  Ea / 8.314  *  -0.00322 -1.134 =  Ea / 8.314  *  -0.00322 Now, solve for Ea:Ea = -1.134 /  -0.00322  * 8.314Ea  2919.6 J/molThe activation energy for the electrochemical reaction between zinc and copper  II  sulfate solution is approximately 2919.6 J/mol.

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