To calculate the resistance of the electrochemical cell, we first need to determine the cell potential under standard conditions Ecell and then use the Nernst equation to find the cell potential under non-standard conditions Ecell . Finally, we can use Ohm's law to calculate the resistance.1. Determine the standard cell potential Ecell :The half-cell reactions are:Cu2+ aq + 2e- Cu s E = +0.34 V reduction Ag+ aq + e- Ag s E = +0.80 V reduction Since the Cu2+ half-cell is being oxidized, we need to reverse the sign of its potential:Cu s Cu2+ aq + 2e- E = -0.34 V oxidation Now, we can calculate the standard cell potential Ecell by adding the two half-cell potentials:Ecell = E Cu2+/Cu + E Ag+/Ag = -0.34 V + 0.80 V = 0.46 V2. Use the Nernst equation to find the cell potential under non-standard conditions Ecell :Ecell = Ecell - RT/nF * ln Q where R is the gas constant 8.314 J/molK , T is the temperature in Kelvin 25C + 273.15 = 298.15 K , n is the number of electrons transferred 2 for Cu2+ and 1 for Ag+; we'll use 2 since it's the lowest common multiple , F is the Faraday constant 96485 C/mol , and Q is the reaction quotient.Q = [Cu2+]/[Ag+] = 2.0 M / 1.0 M = 2Ecell = 0.46 V - 8.314 J/molK * 298.15 K / 2 * 96485 C/mol * ln 2 Ecell 0.46 V - 0.0147 V = 0.4453 VHowever, the problem states that the cell potential is 0.60 V. This discrepancy could be due to the presence of a resistance in the cell, which we will now calculate using Ohm's law.3. Use Ohm's law to calculate the resistance:Ohm's law states that V = IR, where V is the voltage, I is the current, and R is the resistance. We can rearrange this equation to solve for the resistance: R = V/IFirst, we need to find the difference in voltage between the given cell potential 0.60 V and the calculated cell potential under non-standard conditions 0.4453 V :V = 0.60 V - 0.4453 V = 0.1547 VNow, we need to determine the current I flowing through the cell. We can use the cell potential under non-standard conditions Ecell and the number of electrons transferred n to calculate the current using the following equation:I = nFEcellI = 2 * 96485 C/mol * 0.4453 VI 86000 C/molFinally, we can calculate the resistance R using Ohm's law:R = V/I = 0.1547 V / 86000 C/mol 1.80 10^-6 The resistance of the electrochemical cell is approximately 1.80 10^-6 .