To determine the minimum amount of NaCl needed to dissolve in 100 grams of water to form a saturated solution, we need to know the solubility of NaCl in water at room temperature 25C . The solubility of NaCl in water at 25C is approximately 357 grams per liter g/L .First, we need to convert 100 grams of water to liters. The density of water at room temperature is approximately 1 g/mL or 1 g/cm. Therefore, 100 grams of water is equivalent to 100 mL or 0.1 L.Now, we can calculate the amount of NaCl needed to dissolve in 100 grams 0.1 L of water to form a saturated solution:Amount of NaCl = Solubility of NaCl Volume of water Amount of NaCl = 357 g/L 0.1 L Amount of NaCl = 35.7 gSo, the minimum amount of NaCl needed to dissolve in 100 grams of water to form a saturated solution is 35.7 grams.Next, we need to calculate the molar solubility of NaCl in the solution. The molar mass of NaCl is approximately 58.44 g/mol.Molar solubility = Amount of NaCl / Molar mass of NaCl Molar solubility = 35.7 g / 58.44 g/mol Molar solubility 0.611 molTherefore, the molar solubility of NaCl in the saturated solution is approximately 0.611 mol.