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Calculate the standard reaction entropy of the reaction: 2Fe(s) + 3/2O2(g) --> Fe2O3(s) given that the standard enthalpy of the reaction is -824.2 kJ/mol at 298K.

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To calculate the standard reaction entropy, we can use the equation:G = H - TSWhere G is the standard Gibbs free energy change, H is the standard enthalpy change, T is the temperature in Kelvin, and S is the standard entropy change.First, we need to find the standard Gibbs free energy change  G  for the reaction. Since the reaction is balanced and the standard state is defined, we can use the following equation:G = Gf products  - Gf reactants For the given reaction:G = Gf Fe2O3  - [2Gf Fe  + 3/2Gf O2 ]The standard Gibbs free energy of formation  Gf  for elements in their standard state is zero. Therefore, Gf Fe  = 0 and Gf O2  = 0. The Gf Fe2O3  = -740.5 kJ/mol  from standard thermodynamic tables . Substituting these values into the equation:G = -740.5 kJ/mol - [2 0  + 3/2 0 ]G = -740.5 kJ/molNow, we can use the equation G = H - TS to find the standard reaction entropy  S . We are given the standard enthalpy change  H  as -824.2 kJ/mol and the temperature  T  as 298 K. Rearranging the equation to solve for S:S =  H - G  / TSubstituting the given values:S =  -824.2 kJ/mol + 740.5 kJ/mol  / 298 KS =  -83.7 kJ/mol  / 298 KS = -0.281 kJ/ molK The standard reaction entropy for the given reaction is -0.281 kJ/ molK .

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