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Calculate the standard free energy change (ΔG°) for the following redox reaction at 298K:Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s) (Given: E°cell = 1.10V, F = 96,500 J/V.mol)

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To calculate the standard free energy change  G  for the redox reaction, we can use the following equation:G = -nFEcellwhere:G = standard free energy changen = number of moles of electrons transferred in the redox reactionF = Faraday's constant  96,500 J/V.mol Ecell = standard cell potentialFirst, we need to determine the number of moles of electrons transferred in the redox reaction. The balanced half-reactions for the given redox reaction are:Zn s   Zn aq  + 2e  oxidation half-reaction Cu aq  + 2e  Cu s   reduction half-reaction From the balanced half-reactions, we can see that 2 moles of electrons are transferred in the redox reaction. Therefore, n = 2.Now we can calculate G using the equation:G = -nFEcellG = - 2 mol  96,500 J/V.mol  1.10 V G = -212,300 J/molThe standard free energy change  G  for the given redox reaction at 298K is -212,300 J/mol.

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