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Calculate the standard enthalpy of formation (ΔH°f) of carbon dioxide (CO2) at 25°C given the following data:CO(g) + 1/2 O2(g) → CO2(g)    ΔH° = -283.3 kJ/molC(s) + O2(g) → CO2(g)            ΔH° = -393.5 kJ/molΔH°f (C(s)) = 0 kJ/molΔH°f (O2(g)) = 0 kJ/mol

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To calculate the standard enthalpy of formation  Hf  of carbon dioxide  CO2 , we can use the given reactions and their respective enthalpies. We want to find the enthalpy change for the reaction:C s  + O2 g   CO2 g We can use the given reactions to create a reaction pathway that leads to the formation of CO2 from its elements in their standard states. The first reaction is:CO g  + 1/2 O2 g   CO2 g     H = -283.3 kJ/molWe can reverse this reaction to get:CO2 g   CO g  + 1/2 O2 g     H = +283.3 kJ/molNow, we can add the second given reaction:C s  + O2 g   CO2 g             H = -393.5 kJ/molAdding the two reactions together, we get:CO2 g   CO g  + 1/2 O2 g     H = +283.3 kJ/molC s  + O2 g   CO2 g             H = -393.5 kJ/mol---------------------------------------------C s  + 1/2 O2 g   CO g        H = -110.2 kJ/molNow, we can reverse this reaction to get the formation of CO2 from its elements:CO g  + 1/2 O2 g   C s  + O2 g     H = +110.2 kJ/molSince the enthalpy of formation of C s  and O2 g  are both 0 kJ/mol, the standard enthalpy of formation  Hf  of carbon dioxide  CO2  at 25C is:Hf  CO2  = -393.5 kJ/mol

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