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Calculate the standard enthalpy change of formation of magnesium oxide (MgO) using the following data: ΔH°f for Mg (s) = 0 kJ/molΔH°f for O₂ (g) = 0 kJ/mol ΔH°c for MgO (s) = -601.8 kJ/mol

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The standard enthalpy change of formation  Hf  is the enthalpy change when one mole of a compound is formed from its elements in their standard states. In this case, we want to find the Hf for MgO  s  using the given data.The reaction for the formation of MgO from its elements in their standard states is:Mg  s  + 1/2 O  g   MgO  s The standard enthalpy change of formation  Hf  for this reaction can be calculated using Hess's Law, which states that the enthalpy change of a reaction is the sum of the enthalpy changes of the individual steps. In this case, we have:Hf [MgO  s ] = Hc [MgO  s ] - Hf [Mg  s ] - 1/2 Hf [O  g ]Since Hf for Mg  s  and O  g  are both 0 kJ/mol, the equation simplifies to:Hf [MgO  s ] = Hc [MgO  s ]So, the standard enthalpy change of formation of magnesium oxide  MgO  is:Hf [MgO  s ] = -601.8 kJ/mol

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