Calculate the standard enthalpy change for the reduction of iron(III) oxide to iron using the following balanced chemical equation:Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)Given that the standard enthalpy change of formation for Fe2O3(s) is -824.2 kJ/mol, the standard enthalpy change of formation for CO2(g) is -393.5 kJ/mol, and the standard enthalpy change of formation for Fe(s) is 0 kJ/mol. Assume all reactants and products are in their standard states.

Question

Calculate the standard enthalpy change for the reduction of iron(III) oxide to iron using the following balanced chemical equation:Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)Given that the standard enthalpy change of formation for Fe2O3(s) is -824.2 kJ/mol, the standard enthalpy change of formation for CO2(g) is -393.5 kJ/mol, and the standard enthalpy change of formation for Fe(s) is 0 kJ/mol. Assume all reactants and products are in their stan

Answer 1

To calculate the standard enthalpy change for the reaction, we can use the following formula:H =  Hf products  -  Hf reactants where H is the standard enthalpy change for the reaction, and Hf represents the standard enthalpy change of formation for each compound.For the products:2 mol Fe s : 2 * 0 kJ/mol = 0 kJ3 mol CO2 g : 3 *  -393.5 kJ/mol  = -1180.5 kJFor the reactants:1 mol Fe2O3 s : 1 *  -824.2 kJ/mol  = -824.2 kJ3 mol CO g : Since the standard enthalpy of formation for CO g  is not given, we will assume it to be 0 kJ/mol. Therefore, 3 * 0 kJ/mol = 0 kJ.Now, we can plug these values into the formula:H =  0 kJ +  -1180.5 kJ   -   -824.2 kJ  + 0 kJ H = -1180.5 kJ + 824.2 kJH = -356.3 kJThe standard enthalpy change for the reduction of iron III  oxide to iron is -356.3 kJ.