Question

Calculate the standard enthalpy change for the reaction: 2 Al(s) + 3/2 O2(g) → Al2O3(s) given the following information: ΔH°f[Al2O3(s)] = -1676.0 kJ/mol ΔH°f[Al(s)] = 0 kJ/mol ΔH°f[O2(g)] = 0 kJ/mol

Answer 1

To calculate the standard enthalpy change for the reaction, we can use the following equation:Hreaction =  Hf products  -  Hf reactants For this reaction, we have:Hreaction = [1  Hf Al2O3 ] - [2  Hf Al  + 3/2  Hf O2 ]Given the values for the standard enthalpies of formation:Hreaction = [1   -1676.0 kJ/mol ] - [2  0 kJ/mol + 3/2  0 kJ/mol]Hreaction = -1676.0 kJ/molSo, the standard enthalpy change for the reaction is -1676.0 kJ/mol.