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Calculate the standard enthalpy change for the reaction: 2Fe(s) + 3/2 O2(g) -> Fe2O3(s) given that the standard enthalpy of formation for Fe2O3(s) is -824.2 kJ/mol and that of Fe(s) is 0 kJ/mol.

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To calculate the standard enthalpy change for the reaction, we can use the following formula:H reaction  =  Hf products  -  Hf reactants where H reaction  is the standard enthalpy change for the reaction, Hf products  is the sum of the standard enthalpies of formation of the products, and Hf reactants  is the sum of the standard enthalpies of formation of the reactants.For the given reaction:2Fe s  + 3/2 O2 g  -> Fe2O3 s The standard enthalpy of formation for Fe2O3 s  is -824.2 kJ/mol, and that of Fe s  is 0 kJ/mol. The standard enthalpy of formation for O2 g  is also 0 kJ/mol, as it is an element in its standard state.Now, we can plug these values into the formula:H reaction  = [1   -824.2 kJ/mol ] - [2  0 kJ/mol +  3/2   0 kJ/mol]H reaction  = -824.2 kJ/molSo, the standard enthalpy change for the reaction is -824.2 kJ/mol.

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