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Calculate the standard enthalpy change for the reaction 2H2(g) + O2(g) ⟶ 2H2O(g), given that the standard enthalpies of formation of H2(g), O2(g), and H2O(g) are 0 kJ/mol, 0 kJ/mol, and -242 kJ/mol, respectively.
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Chemical thermodynamics
by
PatrickSherr
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Calculate the standard enthalpy change for the reaction 2H2(g) + O2(g) ⟶ 2H2O(g), given that the standard enthalpies of formation of H2(g), O2(g), and H2O(g) are 0 kJ/mol, 0 kJ/mol, and -242 kJ/mol, respectively.
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Jeanett70396
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To calculate the standard enthalpy change for the reaction, we can use the formula:H = Hf products - Hf reactants where H is the standard enthalpy change, and Hf is the standard enthalpy of formation.For the given reaction:2H2 g + O2 g 2H2O g H = [2 Hf H2O g ] - [2 Hf H2 g + Hf O2 g ]Since the standard enthalpies of formation of H2 g and O2 g are 0 kJ/mol:H = [2 -242 kJ/mol ] - [2 0 kJ/mol + 0 kJ/mol]H = -484 kJ/molThe standard enthalpy change for the reaction is -484 kJ/mol.
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