Question

Calculate the standard enthalpy change for the phase transition of ice to water at 298 K, given that the heat of fusion of ice is 6.01 kJ/mol and the molar heat capacity of ice and water are 37.0 J/(mol*K) and 75.3 J/(mol*K), respectively.

Answer 1

To calculate the standard enthalpy change for the phase transition of ice to water at 298 K, we need to consider two steps: 1. Heating the ice from its initial temperature  assumed to be 273 K, the melting point of ice  to the melting point.2. Melting the ice at the melting point  273 K  to form water.Step 1: Heating the ice from 273 K to 298 KH1 = molar heat capacity of ice * TH1 = 37.0 J/ mol*K  *  298 K - 273 K H1 = 37.0 J/ mol*K  * 25 KH1 = 925 J/molStep 2: Melting the ice at 273 KH2 = heat of fusion of iceH2 = 6.01 kJ/molH2 = 6010 J/molNow, we can calculate the total enthalpy change for the phase transition of ice to water at 298 K by adding the enthalpy changes for both steps:H_total = H1 + H2H_total = 925 J/mol + 6010 J/molH_total = 6935 J/molTherefore, the standard enthalpy change for the phase transition of ice to water at 298 K is 6935 J/mol.