To calculate the standard enthalpy change for the neutralization reaction, we can use Hess's Law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for each step in the reaction. In this case, we can consider the formation of the products from their constituent elements, and then subtract the enthalpy of formation for the reactants.The balanced chemical equation for the reaction is:HCl aq + NaOH aq NaCl aq + H2O l The enthalpy change for the reaction H can be calculated using the following equation:H = H products - H reactants For the products, we have:1 mol of NaCl aq with an enthalpy of formation of -411.2 kJ/mol1 mol of H2O l with an enthalpy of formation of -285.8 kJ/molFor the reactants, we have:1 mol of HCl aq with an enthalpy of formation of -92.3 kJ/mol from reference data 1 mol of NaOH aq with an enthalpy of formation of -469.6 kJ/mol from reference data Now, we can plug these values into the equation:H = [ -411.2 kJ/mol + -285.8 kJ/mol ] - [ -92.3 kJ/mol + -469.6 kJ/mol ]H = -696.0 kJ/mol - -561.9 kJ/mol H = -134.1 kJ/molTherefore, the standard enthalpy change for the neutralization reaction between hydrochloric acid and sodium hydroxide is -134.1 kJ/mol.