Question

Calculate the standard enthalpy change for the fusion of 2.5 moles of ice at 0℃ to form water at 0℃. Given that the molar enthalpy of fusion of ice is 6.01 kJ/mol and the specific heat capacity of water is 4.18 J/g·℃.

Answer 1

To calculate the standard enthalpy change for the fusion of 2.5 moles of ice at 0 to form water at 0, we can use the molar enthalpy of fusion of ice.H = n  H_fusionwhere H is the standard enthalpy change, n is the number of moles, and H_fusion is the molar enthalpy of fusion.Given:n = 2.5 molesH_fusion = 6.01 kJ/molH = 2.5 moles  6.01 kJ/mol = 15.025 kJThe standard enthalpy change for the fusion of 2.5 moles of ice at 0 to form water at 0 is 15.025 kJ.