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Calculate the standard enthalpy change for the formation of water vapor (H2O (g)) from its elements, given that the standard enthalpy of formation of hydrogen gas (H2(g)) is -241.8 kJ/mol and the standard enthalpy of formation of oxygen gas (O2(g)) is 0 kJ/mol.

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To calculate the standard enthalpy change for the formation of water vapor  H2O g   from its elements, we need to consider the balanced chemical equation for the formation of water vapor:H2 g  + 1/2 O2 g   H2O g Now, we can use Hess's Law to determine the standard enthalpy change for this reaction. Hess's Law states that the enthalpy change of a reaction is the sum of the enthalpy changes of its individual steps.In this case, the enthalpy change for the formation of water vapor is the difference between the enthalpy of formation of water vapor and the enthalpy of formation of the reactants:H = Hf[H2O g ] -  Hf[H2 g ] + 1/2 Hf[O2 g ] Given that the standard enthalpy of formation of hydrogen gas  H2 g   is -241.8 kJ/mol and the standard enthalpy of formation of oxygen gas  O2 g   is 0 kJ/mol, we can plug these values into the equation:H = Hf[H2O g ] -  -241.8 kJ/mol + 1/2  0 kJ/mol H = Hf[H2O g ] -  -241.8 kJ/mol H = Hf[H2O g ] + 241.8 kJ/molSince we want to find the standard enthalpy change for the formation of water vapor  Hf[H2O g ] , we can rearrange the equation:Hf[H2O g ] = H - 241.8 kJ/molHowever, the given information does not provide the value for H  the enthalpy change for the reaction . Therefore, we cannot calculate the standard enthalpy change for the formation of water vapor  H2O g   from its elements with the given information.

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