To calculate the standard enthalpy change for the dissolution of 5.00 g of solid sodium hydroxide NaOH in water, we first need to determine the number of moles of NaOH being dissolved. The molar mass of NaOH is:Na = 22.99 g/molO = 16.00 g/molH = 1.01 g/molTotal = 22.99 + 16.00 + 1.01 = 40.00 g/molNow, we can find the number of moles of NaOH in 5.00 g:moles = mass / molar massmoles = 5.00 g / 40.00 g/mol = 0.125 molNext, we can use the molar enthalpy of dissolution to find the standard enthalpy change for the dissolution of 5.00 g of NaOH:H = moles molar enthalpy of dissolutionH = 0.125 mol -44.51 kJ/mol = -5.56 kJThe standard enthalpy change for the dissolution of 5.00 g of solid sodium hydroxide in water is -5.56 kJ.