Question

Calculate the standard enthalpy change for the combustion of ethene gas (C2H4(g)) to form carbon dioxide gas (CO2(g)) and water vapor (H2O(g)), given the following thermochemical equations: C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(g)  ΔH°=-1411 kJ/mol2H2(g) + O2(g) → 2H2O(g)   ΔH°=-484 kJ/mol

Answer 1

The given thermochemical equations are:1  C2H4 g  + 3O2 g   2CO2 g  + 2H2O g   H = -1411 kJ/mol2  2H2 g  + O2 g   2H2O g    H = -484 kJ/molWe are asked to find the standard enthalpy change for the combustion of ethene gas  C2H4 g   to form carbon dioxide gas  CO2 g   and water vapor  H2O g  . This is already given in the first equation, so there is no need to manipulate the equations further.The standard enthalpy change for the combustion of ethene gas  C2H4 g   to form carbon dioxide gas  CO2 g   and water vapor  H2O g   is H = -1411 kJ/mol.