0 votes
32 views
ago in ElectroChemistry by (570 points)
Calculate the standard electrode potential of the following cell: Zn(s) | Zn2+(aq) || Cu2+(aq) | Cu(s) Given: Eº(Zn2+(aq)/Zn(s)) = -0.76 V and Eº(Cu2+(aq)/Cu(s)) = +0.34 V.

1 Answer

0 votes
ago by (590 points)
To calculate the standard electrode potential of the given cell, we can use the Nernst equation. However, since we are dealing with standard conditions, the equation simplifies to:E cell  = E cathode  - E anode In this cell, the Zn s  | Zn2+ aq  half-cell acts as the anode  oxidation  and the Cu2+ aq  | Cu s  half-cell acts as the cathode  reduction . We are given the standard electrode potentials for both half-cells:E Zn2+ aq /Zn s   = -0.76 V  anode E Cu2+ aq /Cu s   = +0.34 V  cathode Now, we can plug these values into the simplified Nernst equation:E cell  =  +0.34 V  -  -0.76 V E cell  = +0.34 V + 0.76 VE cell  = +1.10 VThe standard electrode potential of the given cell is +1.10 V.

Related questions

Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...