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Calculate the standard electrode potential of the following cell: Zn(s) | Zn2+(aq) || Cu2+(aq) | Cu(s) Given: Eº(Zn2+(aq)/Zn(s)) = -0.76 V and Eº(Cu2+(aq)/Cu(s)) = +0.34 V.

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To calculate the standard electrode potential of the given cell, we can use the Nernst equation. However, since we are dealing with standard conditions, the equation simplifies to:E cell  = E cathode  - E anode In this cell, the Zn s  | Zn2+ aq  half-cell acts as the anode  oxidation  and the Cu2+ aq  | Cu s  half-cell acts as the cathode  reduction . We are given the standard electrode potentials for both half-cells:E Zn2+ aq /Zn s   = -0.76 V  anode E Cu2+ aq /Cu s   = +0.34 V  cathode Now, we can plug these values into the simplified Nernst equation:E cell  =  +0.34 V  -  -0.76 V E cell  = +0.34 V + 0.76 VE cell  = +1.10 VThe standard electrode potential of the given cell is +1.10 V.

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