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Calculate the standard electrode potential for the reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s) Given that the standard electrode potentials for the half-reactions are: Zn2+(aq) + 2e- → Zn(s)  Etheta = -0.76 V Cu2+(aq) + 2e- → Cu(s) Etheta = 0.34 V

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ago by (550 points)
To calculate the standard electrode potential for the given reaction, we need to subtract the standard electrode potential of the oxidation half-reaction from the standard electrode potential of the reduction half-reaction.First, we need to identify the oxidation and reduction half-reactions. In this case, Zn is being oxidized  losing electrons  and Cu2+ is being reduced  gaining electrons .Oxidation half-reaction: Zn s   Zn2+ aq  + 2e-  reverse of the given Zn half-reaction Reduction half-reaction: Cu2+ aq  + 2e-  Cu s   given Cu half-reaction Now, we need to find the standard electrode potential for the oxidation half-reaction. Since the given Zn half-reaction is the reverse of the oxidation half-reaction, we need to change the sign of its standard electrode potential:Etheta oxidation  = - -0.76 V  = 0.76 VNow, we can calculate the standard electrode potential for the overall reaction:Etheta reaction  = Etheta reduction  - Etheta oxidation Etheta reaction  = 0.34 V - 0.76 VEtheta reaction  = -0.42 VSo, the standard electrode potential for the given reaction is -0.42 V.

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