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Calculate the standard electrode potential for the following redox reaction: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)Given that the standard electrode potential for the Zn²⁺/Zn electrode is -0.76V and for the Cu²⁺/Cu electrode is +0.34V.

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To calculate the standard electrode potential for the given redox reaction, we need to consider the reduction and oxidation half-reactions:1. Oxidation half-reaction: Zn s   Zn aq  + 2e  Zn is oxidized Standard electrode potential for Zn/Zn: E Zn  = -0.76V2. Reduction half-reaction: Cu aq  + 2e  Cu s   Cu is reduced Standard electrode potential for Cu/Cu: E Cu  = +0.34VNow, to find the standard electrode potential for the overall redox reaction, we can use the formula:E cell  = E cathode  - E anode In this case, the Cu/Cu electrode is the cathode  reduction occurs , and the Zn/Zn electrode is the anode  oxidation occurs :E cell  = E Cu  - E Zn  =  +0.34V  -  -0.76V  = +0.34V + 0.76V = +1.10VSo, the standard electrode potential for the given redox reaction is +1.10V.

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