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Calculate the standard electrode potential for the following cell: Mg (s) | Mg2+ (aq, 0.10 M) || Ag+ (aq, 1.0 M) | Ag (s) Given:  E°(Ag+/Ag) = +0.80 V  E°(Mg2+/Mg) = -2.37 V

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To calculate the standard electrode potential for the given cell, we can use the Nernst equation:E_cell = E_cell -  RT/nF  * ln Q where E_cell is the cell potential, E_cell is the standard cell potential, R is the gas constant  8.314 J/molK , T is the temperature in Kelvin  assume 298 K , n is the number of electrons transferred, F is the Faraday constant  96485 C/mol , and Q is the reaction quotient.First, we need to determine the balanced redox reaction and the standard cell potential  E_cell . The half-reactions are:Mg -> Mg + 2e  oxidation 2Ag + 2e -> 2Ag  reduction The balanced redox reaction is:Mg + 2Ag -> Mg + 2AgNow, we can calculate the standard cell potential  E_cell :E_cell = E Ag/Ag  - E Mg/Mg  = 0.80 V -  -2.37 V  = 3.17 VNext, we need to determine the reaction quotient  Q :Q = [Mg]/[Ag]^2 =  0.10 M / 1.0 M ^2 = 0.10Now we can plug the values into the Nernst equation:E_cell = 3.17 V -  8.314 J/molK * 298 K /  2 * 96485 C/mol   * ln 0.10 E_cell = 3.17 V -  0.0257 V  * ln 0.10 E_cell = 3.17 V -  -0.0591 V E_cell = 3.2291 VThe standard electrode potential for the given cell is approximately 3.23 V.

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