Question

Calculate the resistance of an electrochemical cell with a cell potential of 1.5 V and current flow of 0.25 A when the concentration of copper(II) ions in the cathode compartment is 0.25 M and the concentration of zinc ions in the anode compartment is 0.50 M. The cell has two electrodes made of platinum and the temperature is 25°C. (Assume the transfer of electrons and ions is 100% efficient.)

Answer 1

To calculate the resistance of the electrochemical cell, we can use Ohm's Law, which states:V = I  RWhere V is the cell potential  voltage , I is the current flow, and R is the resistance. We can rearrange the formula to solve for R:R = V / IGiven the cell potential  V  is 1.5 V and the current flow  I  is 0.25 A, we can plug these values into the formula:R = 1.5 V / 0.25 AR = 6 The resistance of the electrochemical cell is 6 ohms.