Calculate the resistance of an electrochemical cell given the following parameters: - The cell has a total area of 50 cm² and a separation between the electrodes of 2 cm.- The electrolyte solution has a conductivity of 2.5 × 10⁻⁴ S/cm and a temperature of 25°C.- The electrode on the left side of the cell is made of platinum and has a surface area of 25 cm². The electrode on the right side is made of silver and has a surface area of 25 cm².- The distance between each electrode and the solution is 0.5 cm.

Question

Calculate the resistance of an electrochemical cell given the following parameters: - The cell has a total area of 50 cm² and a separation between the electrodes of 2 cm.- The electrolyte solution has a conductivity of 2.5 × 10⁻⁴ S/cm and a temperature of 25°C.- The electrode on the left side of the cell is made of platinum and has a surface area of 25 cm². The electro

Answer 1

To calculate the resistance of the electrochemical cell, we can use the formula:Resistance  R  = Resistivity     Length  L  / Area  A However, we are given the conductivity    of the electrolyte solution, not the resistivity. Resistivity    and conductivity    are inversely related:Resistivity    = 1 / Conductivity   First, let's find the resistivity of the electrolyte solution: = 1 /  2.5  10 S/cm  = 1 / 0.00025 S/cm = 4000 cmNow, we can calculate the resistance of the electrochemical cell. The length  L  is the separation between the electrodes  2 cm , and the area  A  is the total area of the cell  50 cm :R =  4000 cm  2 cm  / 50 cm = 8000 cm / 50 cm = 160 Therefore, the resistance of the electrochemical cell is 160 .