To calculate the resistance of the electrochemical cell, we need to consider the resistance of the solutions and the resistance of the wire connecting the electrodes.First, let's convert the given units to meters and square meters for easier calculations:Area of each electrode = 10 cm = 0.001 mLength of wire = 30 cm = 0.3 mCross-sectional area of wire = 1 mm = 0.000001 mNow, let's calculate the resistivity of each solution using the given conductivity percentages:_CuSO4 = 1 / 0.983 * _CuSO4 = 1 / 0.983 * 5.95 S/m = 1 / 5.84635 S/m 0.1711 m_ZnSO4 = 1 / 0.899 * _ZnSO4 = 1 / 0.899 * 4.29 S/m = 1 / 3.8581 S/m 0.2591 mNow, we can calculate the resistance of each solution using the formula R = * L / A:R_CuSO4 = 0.1711 m * 0.3 m / 0.001 m 51.33 R_ZnSO4 = 0.2591 m * 0.3 m / 0.001 m 77.73 Next, let's calculate the resistance of the wire. The resistivity of copper is approximately 1.68 10^-8 m. Using the formula R = * L / A:R_wire = 1.68 10^-8 m * 0.3 m / 0.000001 m 5.04 Finally, we can calculate the total resistance of the electrochemical cell by adding the resistances of the solutions and the wire:R_total = R_CuSO4 + R_ZnSO4 + R_wire 51.33 + 77.73 + 5.04 134.1 Therefore, the resistance of the electrochemical cell is approximately 134.1 ohms.