Question

Calculate the reaction quotient (Qc) for the following reaction at 298 K and 1 atm: 2 NO2(g) + F2(g) ⇌ 2 NO2F(g)Given the molar concentrations of reactants and products are [NO2] = 0.25 M, [F2] = 0.15 M, and [NO2F] = 0.10 M at equilibrium.

Answer 1

To calculate the reaction quotient  Qc  for the given reaction, we need to use the formula:Qc = [Products]^coefficients / [Reactants]^coefficientsFor the given reaction:2 NO2 g  + F2 g   2 NO2F g Qc = [NO2F]^2 /  [NO2]^2 * [F2] Now, we can plug in the given molar concentrations:Qc =  0.10 ^2 /   0.25 ^2 *  0.15  Qc = 0.01 /  0.0625 * 0.15 Qc = 0.01 / 0.009375Qc  1.067Therefore, the reaction quotient  Qc  for the given reaction at 298 K and 1 atm is approximately 1.067.