Question

Calculate the number of electrons transferred when a solution containing 0.25 M Ni(NO3)2 is electrolyzed using a current of 0.50 A for 2.0 hours. The reaction taking place is Ni2+ (aq) + 2e- --> Ni (s).

Answer 1

To calculate the number of electrons transferred, we can use the formula:number of electrons = current  A   time  s  / charge of one electron  C First, we need to convert the time from hours to seconds:2.0 hours  3600 seconds/hour = 7200 secondsNow, we can plug in the values into the formula:number of electrons =  0.50 A    7200 s  /  1.6  10^-19 C number of electrons = 3600 C /  1.6  10^-19 C number of electrons = 2.25  10^21 electronsSo, 2.25  10^21 electrons are transferred during the electrolysis of the 0.25 M Ni NO3 2 solution using a current of 0.50 A for 2.0 hours.