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Identify and draw the isomers of C4H10O and explain the type of isomerism exhibited by each isomer.

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C4H10O has three isomers: two alcohols and one ether. Here are the isomers and the type of isomerism they exhibit:1. n-Butanol  1-Butanol Structure: CH3-CH2-CH2-CH2-OHIsomerism: Chain isomerismExplanation: n-Butanol is a straight-chain alcohol with the hydroxyl group  -OH  attached to the terminal carbon atom. Chain isomerism occurs when the carbon skeleton of a molecule is rearranged, resulting in a different structure.2. 2-Butanol  sec-Butanol Structure: CH3-CH2-CH OH -CH3Isomerism: Position isomerismExplanation: 2-Butanol is a branched-chain alcohol with the hydroxyl group  -OH  attached to the second carbon atom. Position isomerism occurs when a functional group is attached to a different carbon atom within the same carbon skeleton.3. Diethyl ether  Ethoxyethane Structure: CH3-CH2-O-CH2-CH3Isomerism: Functional group isomerismExplanation: Diethyl ether is an ether with an oxygen atom connecting two ethyl groups. Functional group isomerism occurs when a molecule has the same molecular formula but different functional groups, in this case, an ether instead of an alcohol.In summary, C4H10O has three isomers: n-butanol, 2-butanol, and diethyl ether. They exhibit chain, position, and functional group isomerism, respectively.
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