A change in the concentration of ligands affects the formation of a complex ion in a solution of FeCl3 by shifting the equilibrium position of the reaction. The complex ion formation can be represented by the following reaction:Fe3+ + nL FeL^nwhere Fe3+ is the metal ion, L is the ligand, and n is the number of ligands attached to the metal ion.The equilibrium constant K for this reaction is given by:K = [FeL^n] / [Fe3+] * [L]^n As the concentration of ligands L increases, the formation of the complex ion FeL^n is favored, and the equilibrium shifts to the right. Conversely, if the concentration of ligands decreases, the equilibrium shifts to the left, favoring the dissociation of the complex ion.The stability constant K_stab of the complex ion is a measure of the strength of the bond between the metal ion and the ligands. It is related to the equilibrium constant K by the following equation:K_stab = [FeL^n] / [Fe3+] * [L]^n As the concentration of ligands increases, the stability constant of the complex ion also increases, indicating a stronger bond between the metal ion and the ligands.To calculate the equilibrium concentrations of the species involved, we need the initial concentrations of Fe3+ and L, as well as the equilibrium constant K for the reaction. Since no specific data is provided, we will use hypothetical values for the calculations.Let's assume the initial concentrations are:[Fe3+] = 0.1 M[L] = 0.2 MK = 10^3At equilibrium, let x moles of L react with Fe3+ to form the complex ion:[Fe3+] = 0.1 - x[L] = 0.2 - nx[FeL^n] = xNow, we can write the equilibrium expression:K = x / 0.1 - x * 0.2 - nx ^n Since K is large 10^3 , we can assume that x is small compared to 0.1 and 0.2. Therefore, we can approximate:K x / 0.1 * 0.2 ^n Solving for x, we get:x 0.1 * 0.2 ^n * KThe equilibrium concentrations of the species involved are:[Fe3+] 0.1 - x[L] 0.2 - nx[FeL^n] xThese values will change at different stages of the reaction, depending on the initial concentrations of Fe3+ and L, as well as the equilibrium constant K for the reaction.