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What is the concentration of copper sulfate in a solution that has an absorbance of 0.332 at a wavelength of 630 nm, given that the molar absorptivity of copper sulfate is 8.8 x 10^3 L/(mol cm)?

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ago by (470 points)
To find the concentration of copper sulfate in the solution, we can use the Beer-Lambert Law, which states:A =  * c * lwhere A is the absorbance,  is the molar absorptivity, c is the concentration of the solute  in this case, copper sulfate , and l is the path length  in cm  through which the light passes.We are given the absorbance  A = 0.332 , the molar absorptivity   = 8.8 x 10^3 L/ mol cm  , and the wavelength  630 nm, which is not needed in this calculation . We will assume the path length  l  is the standard 1 cm. Now, we can solve for the concentration  c :0.332 =  8.8 x 10^3 L/ mol cm   * c * 1 cmTo isolate c, we can divide both sides of the equation by  8.8 x 10^3 L/ mol cm  :c = 0.332 /  8.8 x 10^3 L/ mol cm  c  3.77 x 10^-5 mol/LThe concentration of copper sulfate in the solution is approximately 3.77 x 10^-5 mol/L.

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