To solve this problem, we need to use the following information:1. The molar mass of copper sulfate pentahydrate CuSO45H2O is 249.68 g/mol.2. The total charge required to oxidize one mole of copper ions Cu2+ is 2 Faradays, where 1 Faraday = 96,485 Coulombs/mol.First, we need to find the moles of copper ions Cu2+ that were oxidized during the coulometric titration. We can use the total charge passed 1350 Coulombs and the charge required to oxidize one mole of copper ions 2 Faradays to find the moles of Cu2+.moles of Cu2+ = total charge passed / charge required to oxidize one mole of Cu2+ moles of Cu2+ = 1350 Coulombs / 2 * 96,485 Coulombs/mol moles of Cu2+ = 1350 / 192,970moles of Cu2+ 0.006995 molNow that we have the moles of Cu2+ present in the 40.0 mL of the solution, we can find the concentration of the copper sulfate solution in the 500 mL final volume.First, we need to find the moles of Cu2+ in the 500 mL solution:moles of Cu2+ in 500 mL = 0.006995 mol * 500 mL / 40.0 mL moles of Cu2+ in 500 mL 0.08744 molNow, we can find the concentration of the copper sulfate solution:concentration = moles of Cu2+ / volume of solutionconcentration = 0.08744 mol / 0.500 Lconcentration 0.1749 mol/LTherefore, the concentration of the copper sulfate solution is approximately 0.1749 mol/L.