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What is the concentration of a copper sulfate solution if 40.0 mL of the solution requires 1350 coulombs of charge to fully oxidize all the copper ions present, using a coulometric titration method? The solution was prepared by dissolving a sample of copper sulfate pentahydrate in water and diluting it to a final volume of 500 mL. Given the molar mass of copper sulfate p

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To solve this problem, we need to use the following information:1. The molar mass of copper sulfate pentahydrate  CuSO45H2O  is 249.68 g/mol.2. The total charge required to oxidize one mole of copper ions  Cu2+  is 2 Faradays, where 1 Faraday = 96,485 Coulombs/mol.First, we need to find the moles of copper ions  Cu2+  that were oxidized during the coulometric titration. We can use the total charge passed  1350 Coulombs  and the charge required to oxidize one mole of copper ions  2 Faradays  to find the moles of Cu2+.moles of Cu2+ =  total charge passed  /  charge required to oxidize one mole of Cu2+ moles of Cu2+ = 1350 Coulombs /  2 * 96,485 Coulombs/mol moles of Cu2+ = 1350 / 192,970moles of Cu2+  0.006995 molNow that we have the moles of Cu2+ present in the 40.0 mL of the solution, we can find the concentration of the copper sulfate solution in the 500 mL final volume.First, we need to find the moles of Cu2+ in the 500 mL solution:moles of Cu2+ in 500 mL =  0.006995 mol  *  500 mL / 40.0 mL moles of Cu2+ in 500 mL  0.08744 molNow, we can find the concentration of the copper sulfate solution:concentration = moles of Cu2+ / volume of solutionconcentration = 0.08744 mol / 0.500 Lconcentration  0.1749 mol/LTherefore, the concentration of the copper sulfate solution is approximately 0.1749 mol/L.

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