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What is the concentration (in Molarity) of a hydrochloric acid solution if it requires 25.0 mL of a 0.105 M sodium hydroxide solution for complete neutralization during a titration process?

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ago by (350 points)
To find the concentration of the hydrochloric acid solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between sodium hydroxide  NaOH  and hydrochloric acid  HCl :NaOH + HCl  NaCl + H2OFrom the balanced equation, we can see that the mole ratio between NaOH and HCl is 1:1.We are given the volume and concentration of the sodium hydroxide solution:Volume of NaOH = 25.0 mLConcentration of NaOH = 0.105 MFirst, we need to find the moles of NaOH:moles of NaOH = volume  L   concentration  M moles of NaOH = 0.025 L  0.105 Mmoles of NaOH = 0.002625 molSince the mole ratio between NaOH and HCl is 1:1, the moles of HCl will be equal to the moles of NaOH:moles of HCl = 0.002625 molNow, let's assume that the volume of the HCl solution is V  in liters  and its concentration is C  in Molarity . We can write the equation:moles of HCl = volume  L   concentration  M 0.002625 mol = V  CWe need to find the concentration  C  of the HCl solution. However, we don't have the volume  V  of the HCl solution. Please provide the volume of the HCl solution to calculate its concentration.
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