To determine the amount of CuSO4 present in the sample, we can follow these steps:1. Convert the given current and time to coulombs charge .2. Calculate the moles of electrons transferred.3. Determine the moles of CuSO4.4. Calculate the mass of CuSO4.Step 1: Convert current and time to coulombsCurrent I = 50 mA = 50 x 10^-3 ATime t = 30 minutes = 30 x 60 secondsCharge Q = I x tQ = 50 x 10^-3 A x 30 x 60 s Q = 90,000 x 10^-3 CQ = 90 CStep 2: Calculate the moles of electrons transferredGiven that 30.6 mA-h of charge is consumed, we need to convert this to coulombs as well.Charge consumed = 30.6 mA-h x 1000 mA/A x 3600 s/h Charge consumed = 30.6 A-sMoles of electrons n = Charge consumed / Faraday's constantn = 30.6 A-s / 96485 C/moln 0.000317 molStep 3: Determine the moles of CuSO4The balanced equation for the reduction of CuSO4 is:CuSO4 + 2e- Cu + SO4^2-From the stoichiometry, 1 mole of CuSO4 requires 2 moles of electrons. Therefore,Moles of CuSO4 = Moles of electrons / 2Moles of CuSO4 0.000317 mol / 2Moles of CuSO4 0.0001585 molStep 4: Calculate the mass of CuSO4Molar mass of CuSO4 = 63.5 Cu + 32 S + 4 x 16 O = 159.5 g/molMass of CuSO4 = Moles of CuSO4 x Molar mass of CuSO4Mass of CuSO4 0.0001585 mol x 159.5 g/molMass of CuSO4 0.0253 gTherefore, the amount of CuSO4 present in the given sample is approximately 0.0253 grams.