To determine the amount of copper present in the sample, we can use Faraday's law of electrolysis. Faraday's law states that the amount of substance deposited or dissolved at an electrode during electrolysis is directly proportional to the quantity of charge passed through the electrolyte.First, we need to find the number of moles of electrons n that have been transferred during the electrolysis. We can do this using the formula:n = Q / F * z where:- n is the number of moles of electrons- Q is the charge passed through the electrolyte 12500 C - F is Faraday's constant 96485 C/mol - z is the charge of the ion for copper, Cu, z = 2 since it forms Cu ions n = 12500 C / 96485 C/mol * 2 = 0.0648 molNow that we have the number of moles of electrons, we can find the number of moles of copper deposited:Since the charge of the copper ion is 2 Cu , each mole of copper requires 2 moles of electrons to be deposited. Therefore, the number of moles of copper deposited is equal to half the number of moles of electrons:moles of Cu = 0.0648 mol / 2 = 0.0324 molNow we can find the mass of copper deposited using the molar mass of copper 63.55 g/mol :mass of Cu = moles of Cu * molar mass of Cumass of Cu = 0.0324 mol * 63.55 g/mol = 2.058 gHowever, this value seems to be larger than the initial mass of the copper salt 0.2500 g . There must be a mistake in the given data or the problem statement, as the mass of copper cannot be greater than the mass of the copper salt. Please double-check the values provided and ensure they are correct.