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What is the amount (in moles) of silver ions present in a 0.1M solution of silver nitrate if 1000 coulombs of charge are needed to completely deposit the silver ions onto an electrode during coulometry?

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ago by (570 points)
To solve this problem, we can use Faraday's law of electrolysis, which states that the amount of substance deposited or dissolved at an electrode is directly proportional to the amount of electrical charge passed through the system.The formula for Faraday's law is:moles =  coulombs * n  /  F * valence where:- moles is the amount of substance in moles- coulombs is the amount of electrical charge in coulombs- n is the number of electrons involved in the redox reaction  in this case, 1, since the reaction is Ag+ + e-  Ag - F is Faraday's constant, which is approximately 96485 C/mol- valence is the charge of the ion  in this case, +1 for Ag+ We are given the following information:- coulombs = 1000 C- n = 1  since the reaction is Ag+ + e-  Ag - F = 96485 C/mol- valence = +1  for Ag+ Now we can plug these values into the formula:moles =  1000 C * 1  /  96485 C/mol * 1 moles = 1000 / 96485moles  0.0104 molSo, there are approximately 0.0104 moles of silver ions present in the 0.1M solution of silver nitrate.

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