Question

How many milligrams of lead are present in a 50 mL water sample with a concentration of 0.05 ppm, determined using atomic absorption spectroscopy with a calibration curve?

Answer 1

To find the amount of lead in milligrams present in the 50 mL water sample, we can use the following formula:Amount of lead  mg  = Volume of sample  L   Concentration  mg/L First, we need to convert the volume of the sample from mL to L:50 mL = 50 / 1000 = 0.05 LNext, we need to convert the concentration from ppm to mg/L. Since 1 ppm is equal to 1 mg/L:0.05 ppm = 0.05 mg/LNow, we can plug these values into the formula:Amount of lead  mg  = 0.05 L  0.05 mg/L = 0.0025 mgSo, there are 0.0025 milligrams of lead present in the 50 mL water sample.