0 votes
8 views
in Chemistry by (540 points)
recategorized by
Calculate the mole fraction of each component and the total pressure of a gas mixture at 25°C and 2 atm that contains 0.5 moles of methane (CH4) and 0.2 moles of ethane (C2H6).

1 Answer

0 votes
by (790 points)
selected by
 
Best answer
To calculate the mole fraction of each component, we first need to find the total moles of the gas mixture.

Total moles = moles of methane + moles of ethane
Total moles = 0.5 moles  CH4  + 0.2 moles  C2H6
Total moles = 0.7 moles

Now we can calculate the mole fraction of each component:

Mole fraction of methane  CH4  = moles of methane / total moles
Mole fraction of CH4 = 0.5 moles / 0.7 moles
Mole fraction of CH4 = 0.714  rounded to three decimal places

Mole fraction of ethane  C2H6  = moles of ethane / total moles
Mole fraction of C2H6 = 0.2 moles / 0.7 moles
Mole fraction of C2H6 = 0.286  rounded to three decimal places

Now we can calculate the partial pressures of each component using Dalton's Law of Partial Pressures:

Partial pressure of methane  P_CH4  = mole fraction of CH4 × total pressure
P_CH4 = 0.714 × 2 atm
P_CH4 = 1.428 atm

Partial pressure of ethane  P_C2H6  = mole fraction of C2H6 × total pressure
P_C2H6 = 0.286 × 2 atm
P_C2H6 = 0.572 atm

The total pressure of the gas mixture is the sum of the partial pressures of each component:

Total pressure = P_CH4 + P_C2H6
Total pressure = 1.428 atm + 0.572 atm
Total pressure = 2 atm

So, the mole fractions of methane and ethane are 0.714 and 0.286, respectively, and the total pressure of the gas mixture is 2 atm.

Related questions

Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...