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Calculate the molar mass of magnesium nitrate [Mg(NO3)2].

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To calculate the molar mass of magnesium nitrate [Mg NO3 2], we need to find the molar mass of each element in the compound and then add them together.1. Magnesium  Mg : The molar mass of magnesium is 24.305 g/mol.2. Nitrogen  N : The molar mass of nitrogen is 14.007 g/mol. Since there are two nitrogen atoms in each nitrate ion  NO3-  and two nitrate ions in the compound, there are a total of 4 nitrogen atoms. So, the total molar mass of nitrogen in the compound is 4 * 14.007 g/mol = 56.028 g/mol.3. Oxygen  O : The molar mass of oxygen is 15.999 g/mol. There are three oxygen atoms in each nitrate ion  NO3-  and two nitrate ions in the compound, making a total of 6 oxygen atoms. So, the total molar mass of oxygen in the compound is 6 * 15.999 g/mol = 95.994 g/mol.Now, we add the molar masses of magnesium, nitrogen, and oxygen together:Molar mass of Mg NO3 2 = 24.305 g/mol  Mg  + 56.028 g/mol  N  + 95.994 g/mol  O  = 176.327 g/molSo, the molar mass of magnesium nitrate [Mg NO3 2] is 176.327 g/mol.

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